x^2=63025

Solution for x^2=63025 equation:

x^2=63025

We move all terms to the left:

x^2-(63025)=0

a = 1; b = 0; c = -63025;
Δ = b2-4ac
Δ = 02-4·1·(-63025)
Δ = 252100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{252100}=\sqrt{100*2521}=\sqrt{100}*\sqrt{2521}=10\sqrt{2521}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{2521}}{2*1}=\frac{0-10\sqrt{2521}}{2}
=-\frac{10\sqrt{2521}}{2}
=-5\sqrt{2521}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{2521}}{2*1}=\frac{0+10\sqrt{2521}}{2}
=\frac{10\sqrt{2521}}{2}
=5\sqrt{2521}
$